Answer:
The length of bank side ,s =
unit.
The length of hypotenuse, h= 2 unit.
Explanation:
Given in 30-69-90 triangle
We know that
![tan\theta= \frac {perpendicular}{base}](https://img.qammunity.org/2020/formulas/mathematics/high-school/pj37ovyqxj1tgu4q60d39ofx22fjxa8ghx.png)
![sin\theta=\frac { perpendicular}{ hypotenuse}](https://img.qammunity.org/2020/formulas/mathematics/high-school/thwofod18fcwxpbma3oi1t00mo54tjeksg.png)
When
![\theta=30^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/high-school/cbyn2pcl17wzf11dmi21y1wq52z9zqqzxe.png)
![sin\theta= (1)/(h)](https://img.qammunity.org/2020/formulas/mathematics/high-school/pi8b64rs6wlw7yiucqtwmbfk85hklp61sg.png)
![sin30^(\circ)=\frac {1}{h}](https://img.qammunity.org/2020/formulas/mathematics/high-school/ju3wt15rojkjb5qqvsrak7govyhwxx69xl.png)
![sin30^(\circ)=(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/57g4qtc22jhnt8ezzn5h1gyplnsfnyia4c.png)
Therefore,
![(1)/(h) =(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/1f8a2co4298ry3knk5mtafcnpd20rv0yth.png)
By cross multiply we get
h=2
![tan30^(\circ)=(1)/(s)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8cv9o2haaibwdqkvc87i9a88y8bonu7su2.png)
![tan30^(\circ)=\frac {1}{√(3)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/t0dvutfylrzknjqxo0vrbzwb6duyfyhimv.png)
![(1)/(s) =(1)/(√(3))](https://img.qammunity.org/2020/formulas/mathematics/high-school/8umeu538lxf2lanp4vlbckhx5ixozqpbuv.png)
By cross multiply we get
s=
![√(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3jkdozb6pk3x1px4ym8d058os0wzvynm5a.png)
Hence, the length of side of bank, s=
unit
Length of hypotenuse ,h=2 unit.