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Change each mixed number into an equal improper fraction a. 1 7/16, b. 11 5/9, c. 30 5/9, d. 10 10/13, e. 24 3/5, f. 129 1/2

User Stewsha
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2 Answers

3 votes

Answer:

We need to convert the following fractions into improper fraction.

a.
1 (7)/(16), b.
11 (5)/(9), c.
30 (5)/(9)

d.
10 (10)/(13), e.
24 (3)/(5), and f.
129 (1)/(2)

We know that an improper fraction is a fraction in which the numerator is greater than the denominator.

Now, to convert a mixed fraction, say
a(b)/(c) into improper fraction as,
a(b)/(c)=(a* c+b)/(b)

Now, let us consider each part one by one.

a.
1 (7)/(16)


1(7)/(16)=(16*1+7)/(16) =(23)/(16)

b.
11 (5)/(9)


11(5)/(9)=(11*9+5)/(9) =(104)/(9)

c.
30 (5)/(9)


30(5)/(9)=(30*9+5)/(9) =(275)/(9)

d.
10 (10)/(13)


10(10)/(13)=(10*13+10)/(13) =(140)/(13)

e.
24 (3)/(5)


24(3)/(5)=(24*5+3)/(5) =(123)/(5)

f.
129 (1)/(2)


129(1)/(2)=(129*2+1)/(2) =(259)/(2)

User Daniel Santos
by
8.3k points
7 votes

Answer:

a)


(23)/(16)

b)


(104)/(9)

c)


(275)/(9)

d)


(140)/(13)

e)


(103)/(5)

f)


(259)/(2)

Explanation:

" A fraction in which the numerator is greater than the denominator "

We have to change each of the mixed fraction into improper fraction:

We know that the mixed fraction is converted into fraction as:


a(b)/(c)=(a* c+b)/(c)

a)


1(7)/(16) could be written as:


=(1* 16+7)/(16)\\\\=(16+7)/(16)\\\\=(23)/(16)

b)


11(5)/(9)


=(11* 9+5)/(9)\\\\=(99+5)/(9)\\\\=(104)/(9)

c)


30(5)/(9)


(30* 9+5)/(9)\\\\=(270+5)/(9)\\\\=(275)/(9)

d)


10(10)/(13)


(10* 13+10)/(13)\\\\=(130+10)/(13)\\\\=(140)/(13)

e)


24(3)/(5)\\\\=(24* 5+3)/(5)\\\\=(100+3)/(5)\\\\(103)/(5)

f)


129(1)/(2)\\\\\\=(19* 2+1)/(2)\\\\=(258+1)/(2)\\\\=(259)/(2)

User Chaunv
by
8.3k points

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