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Michael’s weight can be represented by the expression 72x^5. Al’s weight can be represented by the expression 9x^7.

Michael’s weight can be represented by the expression 72x^5. Al’s weight can be represented-example-1

1 Answer

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Answer:

Part A) The ratio is
(72x^(5))/(9x^(7))

Part B)
(8)/(x^(2))

Part C)
8x^(2) ----> The answer change

Explanation:

Let

a------> Michael's weight

b----> Al's weight

we have


a=72x^(5)


b=9x^(7)

Part A) What is the ratio of Michael's weight to Al's weight

we know that


ratio=(a)/(b)

substitute the values


ratio=(72x^(5))/(9x^(7))

Part B) Simplify the ratio from part A)

we have


ratio=(72x^(5))/(9x^(7))

we know that


(72)/(9)=8


(x^(5))/(x^(7))=(1)/(x^(2))

substitute


ratio=(72x^(5))/(9x^(7))=(8)/(x^(2))

Part C) If the exponents in each expression were negative, instead of positive, would that change your answer for part b?

If the exponents in each expression were negative

then

the expression will be


ratio=(72x^(-5))/(9x^(-7))

we know that


(72)/(9)=8


(x^(-5))/(x^(-7))=(x^(7))/(x^(5))=x^(2)

substitute


ratio=(72x^(-5))/(9x^(-7))=8x^(2)

therefore

The answer change

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