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A quadrilateral has vertices (2,2), (2,-2), (-1,2), (-1,2) what special quadrilateral is formed by connecting the midpoint of the sides?

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4 votes

Answer:

Rhombus.

Explanation:

Consider quadrilateral ABDC with vertices at points (2,2), (2,-2), (-1,2), (-1,-2). This quadrilateral is a rectangle. The sides' midpoints are:

  • E(2,0);
  • F(0.5,-2);
  • G(-1,0);
  • H(0.5,2).

Quadrilateral EFGH is always a parallelogram, because midlines EF and GH are parallel to the diagonal AD (by the triangle's midline theorem) and HE, GF are parallel to the diagonal BC. Thus, EF || GH and HE || GF.

Note that


EF=FG=GH=HE=√((2+0.5)^2+(0+2)^2)=√(6.25+4)=√(10.25)\ un.

Thus, this parallelogram is rhombus.

A quadrilateral has vertices (2,2), (2,-2), (-1,2), (-1,2) what special quadrilateral-example-1
User Rifthy
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