Answer:
Option c is the correct answer.
Explanation:
1 -2 3 -2
6 2 2 -48
1 4 3 -38
R2-6R!=R2
R3-R1=R3
1 -2 3 -2
0 14 -16 -36
0 6 0 -36
R3/6=R3
1 -2 3 -2
0 14 -16 -36
0 1 0 -6
The last row gives y =-6
II row gives 14y-16z=-36 : Substitute for y to get z=-3
From I row x-2y+3z=-2
Substitute for y and z
x=-2+2y-3z = -5
Hence correct solution is
(-5,-6,-3)