Question

What are the zeros of 2x^2-6x-8

Answer 1

x=4 x=-1

Explanation:

2x^2-6x-8

Factor out a 2

2(x^2 -3x-4)

What 2 numbers multiply to -4 and add to -3

-4 *1 = -4

-4+1 = -3

2(x-4)(x+1)

Set this equal to zero to find the zero's

2(x-4)(x+1) =0

Using the zero product property

x-4 =0 x+1 =0

x=4 x=-1