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Find the vertex of y=x^2+6x-16​
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Find the vertex of y=x^2+6x-16​

User Amit Beckenstein
by
6.1k points

1 Answer

1 vote

Answer:

(-3,-25)

Explanation:

x^2+6x-16

=(x^2+6x+9)-16-9

=(x+3)^2-25

When a quadratic is written in the form y = a(x–h)^2 + k, the vertex is (h,k).

Vertex=(-3,-25)

User Matias Vad
by
6.6k points
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