Question

A certain quantity of a gas occupies 61.3 mLat 68◦C. If the pressure remains constant,what would the volume of the gas be at 17◦C?1. 52 mL2. 72 mL3. 32 mL4. 92 mL

Answer 1

52 mL

Step-by-step explanation:

Since the pressure of the gas remains constant, we can use the following gas law:

`(V_1)/(T_1)=(V_2)/(T_2)`

where:

`V_1 = 61.3 mL=0.0613 L=0.0613 dm^3 = 6.13\cdot 10^(-5) m^3` is the initial volume

`V_2 = ?` is the final volume

`T_1 = 68^(\circ)C + 273=341 K` is the initial temperature

`T_2 = 17^(\circ)C + 273=290 K` is the final temperature

Substituting numbers and re-arranging the equation, we find the final volume of the gas:

`V_2=(T_2)/(T_1)V_1 = (290 K)/(341 K)(6.13\cdot 10^(-5) m^3)=5.21\cdot 10^(-5) m^3 = 52.1 mL`

So the correct answer is

1. 52 mL