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A certain quantity of a gas occupies 61.3 mLat 68◦C. If the pressure remains constant,what would the volume of the gas be at 17◦C?1. 52 mL2. 72 mL3. 32 mL4. 92 mL

1 Answer

3 votes

Answer:

52 mL

Step-by-step explanation:

Since the pressure of the gas remains constant, we can use the following gas law:


(V_1)/(T_1)=(V_2)/(T_2)

where:


V_1 = 61.3 mL=0.0613 L=0.0613 dm^3 = 6.13\cdot 10^(-5) m^3 is the initial volume


V_2 = ? is the final volume


T_1 = 68^(\circ)C + 273=341 K is the initial temperature


T_2 = 17^(\circ)C + 273=290 K is the final temperature

Substituting numbers and re-arranging the equation, we find the final volume of the gas:


V_2=(T_2)/(T_1)V_1 = (290 K)/(341 K)(6.13\cdot 10^(-5) m^3)=5.21\cdot 10^(-5) m^3 = 52.1 mL

So the correct answer is

1. 52 mL

User Tillias
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