Question

PLZ HELP CHEM!!!!!!!!!!!!!!

Answer 1

the third answer 42.6L

Answer 2

The volume of the 84 grams of bromine gas at STP is 11.77 L.

Step-by-step explanation:

Mass of bromine gas = 84 g

Moles of bromine gas =
`(84 g)/(160 g/mol)=0.525 mol`

where,

P = Pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles of gas = 0.0525 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K (at STP)

Putting values in above equation, we get:

`V=(nRT)/(P)`

`V=(0.525 mol* 0.0821 atm L/mol K* 273.15 K)/(1 atm)`

V = 11.77 L

The volume of the 84 grams of bromine gas at STP is 11.77 L.