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Factor completely: 12x^5 + 6x^3 + 8x^2 a- prime b- 2(6x^5+3x^3+4x^2) c- 2x(6x^4+6x^2+4x) d- 2x^2(6x^3+3x+4)
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1 vote
Factor completely:

12x^5 + 6x^3 + 8x^2

a- prime
b- 2(6x^5+3x^3+4x^2)
c- 2x(6x^4+6x^2+4x)
d- 2x^2(6x^3+3x+4)

User Song Kevin
by
8.9k points

1 Answer

4 votes

Answer:

d

Explanation:

Given

12
x^(5) + 6x³ + 8x² ← factor out 2x² from each term

= 2x²(6x³ + 3x + 4) → d

User Zsolt Safrany
by
7.7k points
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