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Factor completely: 4x^2 + 16x a- 4(x^2+4x) b- x(4x+16) c- 4x(x+4) d- prime
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3 votes
Factor completely:

4x^2 + 16x
a- 4(x^2+4x)
b- x(4x+16)
c- 4x(x+4)
d- prime

User Fordio
by
8.3k points

1 Answer

3 votes

Answer:

4x(x + 4)

Explanation:

Given

4x² + 16x ← factor out 4x from each term

= 4x(x + 4)

User Terrific
by
8.2k points
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