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1 vote
What is the equation of the graph below?

What is the equation of the graph below?-example-1
User Rethinavel
by
8.4k points

2 Answers

4 votes

Answer:A

Explanation:

look at the graph and u will find the same answer

User Javiertoledos
by
8.6k points
7 votes

Answer: The correct option is (A)
y=\sin(x+90^\circ).

Step-by-step explanation: We are to select the correct equation of the given graph.

From the graph, we can see that

y (x = 0) = 1,

y (x = 90°) = 0,

y (x = -90°) = 0,

y (x = 180°) = -1,

y (x = -180°) = -1, etc.

Option (A) is


y=\sin(x+90^\circ).

We have


y(x=0)=\sin(0+90^\circ)=\sin90^\circ=1,\\\\y(x=90^\circ)=\sin(90^\circ+90^\circ)=\cos90^\circ=0,\\\\y(x=-90^\circ)=\sin(-90^\circ+90^\circ)=\sin0^\circ=0,\\\\y(x=180^\circ)=\sin(180^\circ+90^\circ)=-\sin90^\circ=-1,\\\\y(x=-180^\circ)=\sin(-180^\circ+90^\circ)=-\sin90^\circ=-1,~etc.

So, this option is correct.

Option (B) is


y=\cos(x+90^\circ).

We have


y(x=0)=\cos(0+90^\circ)=\cos90^\circ=0\\eq 1.

So, this option is not correct.

Option (C) is


y=\sin(x+45^\circ).

We have


y(x=0)=\sin(0+45^\circ)=\sin45^\circ=(1)/(\sqrt2)\\eq 1.

So, this option is not correct.

Option (D) is
y=\sin(x+90^\circ).


y=\cos(x+45^\circ).

We have


y(x=0)=\cos(0+45^\circ)=\cos45^\circ=(1)/(\sqrt2)\\eq 1.

So, this option is also not correct.

Thus, the correct option is (A)

User SwethaKandikonda
by
8.7k points

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