Question

0=16t^2+159
show your work please

Answer 1

t = (i sqrt(159))/4 or t = -(i sqrt(159))/4

Explanation:

Solve for t:

0 = 16 t^2 + 159

0 = 16 t^2 + 159 is equivalent to 16 t^2 + 159 = 0:

16 t^2 + 159 = 0

Subtract 159 from both sides:

16 t^2 = -159

Divide both sides by 16:

t^2 = -159/16

Take the square root of both sides:

Answer: t = (i sqrt(159))/4 or t = -(i sqrt(159))/4