Question

What are the vertices of triangle A'B'C' produced by (x, y) -> (x+5, y-2)?

Answer 1

The vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:

• A'(8, -2)

• B'(8, 0)

• C'(5, -5)

Explanation:

Given the vertices of an original triangle ΔABC such that

• A = (3, 0)

• B = (3, 2)

• C = (0, -3)

As the rule of translation is given by

Translation: (x, y) → (x+5, y-2)

So, after the translation the vertices of the original triangle ΔABC will be translated as:

A = (3, 0) → (x+5, y-2) ⇒ (3+5, 0-2) = A'(8, -2)

B = (3, 2) → (x+5, y-2) ⇒ (3+5, 2-2) = B'(8, 0)

C = (0, -3) → (x+5, y-2) ⇒ (0+5, -3-2) = C'(5, -5)

Therefore, the vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:

• A'(8, -2)

• B'(8, 0)

• C'(5, -5)