Question

I want to prepare 4 Liters of 0.25 M aqueous sodium chloride solution. How many grams of the salt will I need to weigh out?

Answer 1

To prepare the 4 liters of 0.25 M sodium chloride solution, you will need to weigh out 58.44 grams of the salt.

Step-by-step explanation:

To prepare 4 Liters of 0.25 M aqueous sodium chloride solution, you need to calculate the number of moles of sodium chloride required using the formula:

Moles = volume (in L) x concentration (in M)

So, moles = 4 L x 0.25 M = 1 mole

The molar mass of sodium chloride (NaCl) is 58.44 g/mol. Therefore, you would need to weigh out 1 mole x 58.44 g/mol = 58.44 grams of sodium chloride to prepare the solution.

Answer 2

Mass = 58.5 g

Step-by-step explanation:

Given data:

Volume of solution = 4 L

Molarity of solution = 0.25 M

Grams of NaCl required = ?

Solution:

Formula:

Molarity = number of moles / volume in L

By putting values,

0.25 M = number of moles / 4 L

Number of moles = 0.25 mol/L × 4 L

Number of moles = 1 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 1 mol × 58.5 g/mol

Mass = 58.5 g