Question

What is the area of this area?????

Answer 1

`\large\boxed{A=153\ in^2}`

Explanation:

We have the ractangle and the trapezoid.

The formula of an area of a rectangle:

`A_(rectangle)=lw`

l - length

w - width

The formula of an area of a trapezoid:

`A_(trapezoid)=(b_1+b_2)/(2)\cdot h`

b₁, b₂ - bases

h - height

RECTANGLE:

l = 3 in, w = 16 in

`A_(rectangle)=(3)(16)=48\ in^2`

TRAPEZOID:

b₁ = 16 in, b₂ = 5 in, h = 10 in

`A_(trapezoid)=(16+5)/(2)\cdot10=(21)/(1)\cdot5=105\ in^2`

The area of the figure:

`A=A_(rectangle)+A_(trapezoid)`

Substitute:

`A=48+105=153\ in^2`

Answer 2

=153 in^2

Explanation:

We have a rectangle and a trapezoid

We can add the areas together

The area of the rectangle is

A = l*w where l =16 and w =3

A = 16*3 = 48 in^2

The area of the trapezoid

A = 1/2 (b1+b2)*h where b1 =16, b2=5 and h = 10

A = 1/2 (16+5) *10

= 1/2 (21) *10

=105 in^2

Then we add the areas together

A total = A rectangle + A trapezoid

A total = 48+ 105

=153 in^2