Question

Axis of symmetry of h=-16t^2+20t+6​

Answer 1

t =
`(5)/(8)`

Explanation:

Given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the axis of symmetry is

x = -
`(b)/(2a)`

h = - 16t² + 20t + 6 is in standard form

with a = - 16 and b = 20, hence

t = -
`(20)/(-32)` =
`(5)/(8)` ← axis of symmetry