Question

Factor Completely.3g^2-78g+75

Answer 1

Answer:(3g-75)(g-1)

Explanation:

3g^2-78g+75

3g^2-3g+75g-75

3g(g-1)+75(g-1)

(3g-75)(g-1)

Answer 2

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❖ 3g^2 - 78g + 75 factored completely is
`3(g-1) * (g-25)`

First, write the expression as a difference:

`3(g^(2) -26g +25)`

Then factor the expression:

`3(g^(2) - g - 25g + 25)`

Factor the expression again:

`3 (g*(g-1)-25(g-1))`

Your final answer should be:

`3(g-1)*(g-25)`

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