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"Alexis, Becca, and Cindy do volunteer work at Adopt-a-Pet Animal Shelter. They worked a total of 285 hours at the shelter last summer. Alexis worked 15 hours less than Becca. Cindy worked 4 more than twice as many hours as Becca."

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User Loredra L
by
5.6k points

2 Answers

3 votes

Answer:

Alexis = 59

Becca = 74

Cindy = 152

Explanation:

a + b + c = 285

a = b - 15

c = 2b + 4

User Krdx
by
5.1k points
6 votes

Answer:

Alexis worked 59 hours, Cindy worked 152 hours and Becca worked 74 hours.

Explanation:

Givens

  • They worked a total of 285 hours.
  • Alexis worked 15 hours less than Becca.
  • Cindy worked 4 more than twice as many hours as Becca.
  • Alexis is
    A.
  • Cindy is
    C
  • Becca is
    B

The expressions that model this problem would be


A+C+B=285

Because all together they work 285 hours.


A=B-15

Because Alexis worked 15 hours less than Becca.


C=4+2B

Because Cindy worked 4 hours more than twice Becca's hours

Now, we replace the last two expression in the first one


B-15+4+2B+B=285\\4B-11=285\\4B=285+11\\B=(296)/(4)=74

Then, we replace this value to find others


C=4+2B=4+2(74)=152


A=B-15=74-15=59

Therefore, Alexis worked 59 hours, Cindy worked 152 hours and Becca worked 74 hours.

User RiverTwilight
by
5.4k points