Question

If the domain of the function
f (x)=2x^2-8 is (-2,3,5) then the range is​

Answer 1

The range of the function f(x) = 2x^2 - 8 for the domain (-2, 3, 5) is {0, 10, 42}.

Step-by-step explanation:

To find the range of the function f(x) = 2x^2 - 8 for the domain (-2, 3, 5), we will substitute each domain value into the function and calculate the corresponding output values.

f(-2) = 2*(-2)^2 - 8 = 2*4 - 8 = 8 - 8 = 0

f(3) = 2*3^2 - 8 = 2*9 - 8 = 18 - 8 = 10

f(5) = 2*5^2 - 8 = 2*25 - 8 = 50 - 8 = 42

The range, which is the set of all output values (function values), for this particular domain will be {0, 10, 42}.

Answer 2

The range: {0, 10, 42}

Step-by-step explanation:

Put the values of x from the domain to the equation of the function

f(x) = 2x² - 8

for x = -2

f(-2) = 2(-2)² - 8 = 2(4) - 8 = 8 - 8 = 0

for x = 3

f(3) = 2(3)² - 8 = 2(9) - 8 = 18 - 8 = 10

for x = 5

f(5) = 2(5)² - 8 = 2(25) - 8 = 50 - 8 = 42