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I need step by step answer ​-example-1
User Mohd Ahmed
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Answer: 10⁻⁸°⁹

Explanation:


pH=log\bigg((1)/([H^+])\bigg)\\\\\text{use log expansion rules to get:}\\pH=log\ 1-log\ [H^+]\\\\8.9=0\ -\ log\ [H^+]\\\\8.9=-log\ [H^+]\\\\-8.9=log\ [H^+]\\\\\text{use log transformation rules to get the following exponential equation:}\\10^(-8.9)=[H^+]

User Cobie
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