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An oval track is made by enclosing semicircles on each end of a 58 m by 116 m rectangle. Find the area enclosed by the track. Use 3.14 for pi.

User Proffesor
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2 Answers

6 votes

Answer:116

Explanation:

I hope that helped :)

User Marc Fischer
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2 votes

IF the semicircle is on the 58m end then:

L=2*116+3.14*58

L=232+3.14*58

L=232+182.12=414.12 m. ans. for the length.

A=58*114+3.14(58/2)^2

A=6,612+3.14(29)^2

A=6,612+3.14*841

A=6,612+2,640.74

A=9,252.74 m^2. ans.

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IF the semicircircle is on the 116m end then just replace the 58 by 116.

User SENya
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7.6k points
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