Question

A quadratic function has a line of symmetry at X equals -3.5 and a zero at-9 what is the distance from the given zero of the line of symmetry

Answer 1

Answer: 12.5

Explanation:

(9,0) (-3.5,0)

Distance formula

√(x2-x1)²+(y2-y1)²

√(9-(-3.5))²+(0-0)²

√(12.5)²

√156.25

12.5

Answer 2

5.5

Explanation:

Solved it on edge. Don't wanna show the work but trust me, it's right.