Question

I need this immediately!! Put the equation in standard form with a positive X coefficient. Y + 6 = 3/2 ( x - 4 ) HELP!! ​

Answer 1

3/2x -y = 12

Explanation:

Y + 6 = 3/2 ( x - 4 )

Distribute the 3/2

y+6 = 3/2x - 12/2

y+6 = 3/2x -6

Subtract 6 from each side

y+6-6 = 3/2x -6-6

y = 3/2x -12

Subtract 3/2x from each side

-3/2x +y = 3/2x-3/2x -12

-3/2x +y = -12

We want a positive x so multiply by -1

-1(-3/2x +y) = -1* -12

3/2x -y = 12

Answer 2

see explanation

Explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

given

y + 6 =
`(3)/(2)`(x - 4)

Multiply through by 2 to eliminate the fraction

2y + 12 = 3(x - 4) ← distribute

2y + 12 = 3x - 12 ( subtract 2y from both sides )

12 = 3x - 2y - 12 ( add 12 to both sides )

24 = 3x - 2y, that is

3x - 2y = 24 ← in standard form