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Helppp plzzzzz mathhh

2) find f^-1 for the function f(x)=∛x-2+8

A) f^-1(x)=(x-8)^3+2

B)f^-1(x)=(x+8)^3+2

C)f^-1(x)=∛x-8+2

D)f^-1(x)=(x-8)^3-2

User SUNDONG
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1 Answer

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Answer:

A) f^-1(x)=(x-8)^3+2

Explanation:

To find the function inverse, switch the x with y and solve for y.


y=\sqrt[3]{x-2}+8 \\\\x=\sqrt[3]{y-2}+8\\\\(x-8)^3 = y-2\\\\ (x-8)^3 + 2 = y

User Malfet
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