Question

(a) Complete the table of values for y = 6 - 4x.

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Answer 1

`\boxed{\begin{tabular}c\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}}`

Explanation:

Given equation to us is :-

`\implies y = 6 - 4x`

So , here we can put different values of x in order to get different values of y .

Initial table given to us is ,

`\begin{tabular}c\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & & & 2&&-6 \\\cline{1-6}\end{tabular}`

Put x = (-1) :-

`\implies y = 6 - 4x \\\\\implies y = 6 -4(-1) \\\\\implies y = 6 + 4 \\\\\red{\bf\implies y = 10}`

Put x = 0 :-

`\implies y = 6 - 4x \\\\\implies y = 6-4(0) \\\\\implies y = 6 - 0 \\\\\pink{\bf\implies y = 6 }`

Put x = 2 :-

`\implies y = 6-4x \\\\\implies y = 6 - 4(2) \\\\\implies y = 6 - 8 \\\\\blue{\bf\implies y = (-2)}`

Hence the final table would be :-

`\begin{tabular}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}`