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Is the equation x^9-5x^3+6=0 quadratic in form Explain why or not

2 Answers

4 votes

Answer:

The given equation, x9 - 5x3 + 6 = 0, is not a quadratic equation because the exponent of the first term is 9 while that of the second term is 3. The square of 3. If we are to square x3, we should only be getting x6 instead of x9. Therefore, the answer is NO.

Explanation:

User Busches
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7 votes

Answer:

No, the equation is not in quadratic form.

Explanation:

We have
x^9-5x^3+6=0,

The quadratic equations have the form
ax^2+bx+c=0 with
a\\eq 0

In this case we have the first term
x^9 raised to the ninth, and we can see that a quadratic equation has the first term squared.

The second term
5x^3 is raised to the cube, and the quadratic equation has the second term raised to one.

Then the equation
x^9-5x^3+6=0 isn't a quadratic equation.

User Radia
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5.6k points