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Nitesh Kothari asked Jul 2, 2023

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Nitesh Kothari asked Jul 2, 2023

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6 votes

Answer:
$(1)/(3) \sin x^(3)+C$

Explanation:

Let
u=x^3 . Then,
$3x^2 dx = du \longrightarrow x^2 dx =(1)/(3)du$

So, we can rewrite the original integral as

$(1)/(3) \int \cos u \text{ } du=(1)/(3) \sin u+C=(1)/(3) \sin x^(3)+C$

Boketto answered Jul 8, 2023

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