Question

If x=z+8 where z varies inversely as y and z=2 when y=3 find relation between y and x?​

Answer 1

y = 6/(x - 8).

Explanation:

z = k/y where k is a constant

2 = k/3

k = 6.

So z = 6/y

and x = 6/y + 8

Multiply through by y:

xy = 6 + 8y

xy - 8y = 6

y(x - 8) = 6

y = 6/(x - 8)