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A 1 kg ball is tossed straight up with a kinetic energy of 196 j how high does it go

2 Answers

7 votes

Final answer:

The height that the ball will reach can be determined by using the principle of conservation of energy. The height is 20 meters.

Step-by-step explanation:

The height that the ball will reach can be determined by using the principle of conservation of energy. In this case, we can use the fact that the initial kinetic energy of the ball is equal to the change in its potential energy as it reaches the highest point in its trajectory.

Given that the kinetic energy of the ball is 196 J, we can equate this to the potential energy at the highest point:

196 J = m * g * h

Solving for h:

h = 196 J / (m * g)

Plugging in the values of m (1 kg) and g (9.8 m/s²), we can calculate the height:

h = 196 J / (1 kg * 9.8 m/s²)

h = 20 m

User Neile
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5.1k points
4 votes

20m is the right answer

User Teneff
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4.7k points