Question

Pleaseeee help meeeee


What is ∑n=125(3n−2) equal to?

Answer 1

925 is your answer!

Explanation:

Hope this helps!

Answer 2

`\sum_(n=1)^(25)(3n-2)=925]`

Explanation:

The given series is
`\sum_(n=1)^(25)(3n-2)`

The first term of this series is

`a_1=3(1)-2`

`a_1=3-2`

`a_1=1`

The second term is

`a_2=3(2)-2`

`a_2=6-2`

`a_2=4`

The common difference is

`d=4-1=3`

The sum of the first n-terms is given by;

`S_n=(n)/(2)[2a_1+d(n-1)]`

The sum of the first 25 terms of the series is

`S_(25)=(25)/(2)[2(1)+3(25-1)]`

`S_(25)=(25)/(2)[2+3(24)]`

`S_(25)=(25)/(2)(74)]`

`S_(25)=925]`