Question

How do you verify it

Answer 1

see explanation

Explanation:

Using the trigonometric identities

• csc x =
`(1)/(sinx)` and sec x =
`(1)/(cosx)`

• sin2x = 2sinx cosx

Consider the left side

2 csc 2x = 2 ×
`(1)/(sin2x)`

= 2 ×
`(1)/(2sinxcosx)` ( cancelling the 2's )

=
`(1)/(sinx)` ×
`(1)/(cosx)`

= cscx secx = right side ⇒ verified