Question

Mid point of A(-7,1) and B (3,-5)

Answer 1

`let \: m \: be \: the \: mid \: point \\ m = (( \frac{( {x}^(1) + {x}^(o))}{2}) \: \: \: ( \frac{ ({y}^(1) + {y}^(o)) }{2} )) \\ m = (( (( - 7 + 3))/(2) ) \: \: \: ( ((1 + - 5))/(2) ) \\ m = ( ( - 4)/(2) \: \: \: ( - 4)/(2) ) \\ m = ( - 2 \: \: \: - 2) \\ mid \: point \: = \: \binom{ - 2}{ - 2}`

Answer 2

(-2,-2)

Explanation:

use midpoint formula: (average of two x-values, average of two y-values)

(-7 + 3)/2 = -4/2 = -2

(1 + -5)/2 = -4/2 = -2