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graph the function n(x) = (x-1)^2 -7. compare the graph to the graph of f(x) = x^2. i have the vertex which is (-1,-7) how do I get the other two points on the graph to make a parabla?​

User Coolsv
by
5.4k points

1 Answer

5 votes

Answer:

See below.

Explanation:

To find the other two points such as the x-intercepts, set the equation equal to 0 and solve for x.


0 = (x-1)^2 -7\\\\7 = (x-1)^2\\\\√(7) = √((x-1)^2) \\\\+/-√(7) = (x-1)\\1+/-√(7) = x

This means the points will be at (3.64, 0) and (-1.64, 0).

This graph is shifted 1 unit to the right and 7 units down from x^2.

User Alphaaa
by
5.2k points
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