2 Answers

Rebeku · Answer 1 · 2020-07-13T19:14:30+0000

Answer : The theoretical mass of sodium sulfate produced is, 514.04 grams

Solution : Given,

Mass of sulfuric acid = 355 g

Molar mass sulfuric acid = 98 g/mole

Molar mass of sodium sulfate = 142 g/mole

First we have to calculate the moles of sulfuric acid.

$\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}=(355g)/(98/mole)=3.62moles$

Now we have to calculate the moles of sodium sulfate.

The given balanced reaction is,

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

From the balanced reaction, we conclude that

As, 1 mole of sulfuric acid react to give 1 mole of sodium sulfate

So, 3.62 mole of sulfuric acid react to give 3.62 mole of sodium sulfate

Now we have to calculate the theoretical mass of sodium sulfate.

$\text{Mass of }Na_2SO_4=\text{Moles of }Na_2SO_4* \text{Molar mass of }Na_2SO_4}$

$\text{Mass of }Na_2SO_4=3.62mole* 142g/mole=514.04g$

Therefore, the theoretical mass of sodium sulfate produced is, 514.04 grams

Grigore Budac · Answer 2 · 2020-07-18T20:56:33+0000

Answer:

514.53 g.

Step-by-step explanation:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O.

It is clear that 2.0 moles of NaOH reacts with 1.0 mole of H₂SO₄ to produce 1.0 mole of Na₂SO₄ and 2.0 moles of H₂O.

n = mass / molar mass = (355.0 g) / (98.0 g/mol) = 3.62 mol.

Using cross multiplication; we can calculate the no. of moles of sodium sulfate Na₂SO₄ can the reaction produce:

1.0 mole of H₂SO₄ produces → 1.0 mole of Na₂SO₄, from the stichiometry.

3.62 moles of H₂SO₄ produces → ??? mole of Na₂SO₄.

The no. of moles of sodium sulfate Na₂SO₄ can the reaction produce = (1.0 mol)(3.62 mol) / (1.0 mol) = 3.62 mol.

Now, we can calculate the grams (mass) of sodium sulfate Na₂SO₄ can the reaction produce = n x molar mass = (3.62 mol)(142.04 g/mol) = 514.53 g.

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