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Find the solution set of the inequality. \qquad16x - 7 \leq -7116x−7≤−71

User Nick Jonas
by
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2 Answers

2 votes

Answer:

x < -4

I did this on khan academy

User Lakota
by
8.0k points
8 votes

Answer:


x \le -4

Explanation:

Given


\qquad16x - 7 \leq -71

Required

Solve

Start by adding 7 to both sides


\qquad16x - 7 + 7 \leq -71 + 7


\qquad16x - 7 + 7 \leq -64


\qquad16x \leq -64

Divide both sides by 16


(16x)/(16) \leq (-64)/(16)


(16x)/(16) \leq -(64)/(16)


x \leq -(64)/(16)


x \le -4 --- The solution

User Chrismcg
by
8.0k points

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