![a =7000](https://img.qammunity.org/2020/formulas/mathematics/college/ncini1ralqj0g57khhp73uj155y2uwp4ed.png)
![b = 0.4](https://img.qammunity.org/2020/formulas/mathematics/college/pdcpui8eekeujgtwxkb98wwy9hyb0b2xyv.png)
Step by step:
Firstly, we should substitute the points where x is equal to 0 so that we can obtain the a value
![7000 = a {b}^(0)](https://img.qammunity.org/2020/formulas/mathematics/college/fsnstszz3gb8jmeo9mn2go6fhf77ihylj1.png)
And because anything to the power of 0 is 1
![7000 \: = a * 1 = a](https://img.qammunity.org/2020/formulas/mathematics/college/2bsf08kh3hal9w6j2xj1s0t01cnwqd39zd.png)
Now that we have the value for a, we can substitute it into the 2nd equation to find b
![1120 = 7000 {b}^(2)](https://img.qammunity.org/2020/formulas/mathematics/college/ss1u6zuii0sy3rh5cn19ijw36mjc3l0a2a.png)
Finally, we rearrange to make b the subject
![(1120)/(7000) = {b}^(2) \\ \sqrt{ (1120)/(7000) } = b \\ b = 0.4](https://img.qammunity.org/2020/formulas/mathematics/college/ob8t93oeqvm850e0hebrd8kguz9cuhxbkt.png)