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What are the zero of f(x)=x^2-10x+25

What are the zero of f(x)=x^2-10x+25-example-1

2 Answers

3 votes

Answer:

D. x = 5 only

Explanation:

x^2 - 10x + 25 = 0

(x +/- ?) (x +/- ?) = 0

-5 X -5 = 25

-5 + -5 = -10

(x - 5) (x - 5)

x = 5, x = 5

User Alveona
by
8.1k points
1 vote

Hello from MrBillDoesMath!

Answer:

x = 5 only

Discussion:

x^2 - 10x + 25.

Note that (-5)*(-5) = 25, the constant term in f(x), and -5 + -5 = -10, the coefficient of x in f(x). This suggests that the factorization of f(x) is

f(x) = (x-5)^2

Hence f has a single (repeated or double) root, x = 5, which is Choice D

Thank you,

MrB

User John Robins
by
8.9k points

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