Answer:
1. y = -x - 1
2. y = (3/2)x - 4
Explanation:
1. Let y = ax + b be the equation of the line
that passes Through (4,-5) and parallel to y = -x + 1
Where ‘a’ is the slope and b the y value of the y-intercept point.
The lines are parallel
then
they have the same slope
then
a = -1
we get :
y = -x + b and the point (4 , -5) lies on the line
then
-5 = -(4) + b
Then
b = -5 + 4 = -1
Conclusion:
y = -x - 1
………………………………………
2. Let y = mx + p be the equation of the line
that passes Through (2,-1) and perpendicular to y = -2/3x + 5
Where ‘m’ is the slope and p the y value of the y-intercept point.
The lines are perpendicular
then
The product of their slopes = -1
Then
m × (-2/3) = -1
Then
m = 3/2
we get :
y = 3/2x + p and the point (2 , -1) lies on the line
then
-1 = (3/2)×(2) + p
Then
p = -1 - 3 = -4
Conclusion:
y = (3/2)x - 4