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Find the dimensions of the rectangle

A. 5x8
B. 2x6
C. 3x6
D. 2x3

Find the dimensions of the rectangle A. 5x8 B. 2x6 C. 3x6 D. 2x3-example-1
User Ancoron
by
8.0k points

1 Answer

4 votes

Answer: choice B) 2 by 6

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How I got that answer:

Opposite sides of the rectangle are the same length, so

y = 2x-4 (horizontal sides)

3y = x+3 (vertical sides)

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Start with the second equation. Replace the 'y' with (2x-4) which is from the first equation. This replacement will allow us to solve for y

3y = x+3

3(2x-4) = x+3 .. replaced y with (2x-4)

6x-12 = x+3 ... distribute

6x-12+12 = x+3+12 ..... add 12 to both sides

6x = x+15

6x-x = x+15-x ..... subtract x from both sides

5x = 15

5x/5 = 15/5 ........ divide both sides by 5

x = 3

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Now we know the value of x, which means we can find the value of y

y = 2x-4

y = 2*3-4 .... replace x with 3

y = 6-4

y = 2

So the horizontal side is 2 units long

The vertical side is therefore 3y = 3*2 = 6

or we can say x+3 = 3+3 = 6 getting the same answer

User Olibiaz
by
8.4k points
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