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according to the fundamental theorem of algebra, how many zeros does the function f(x)= (x-15)(x+1)(x-10)?

2 Answers

4 votes

Answer:

The correct answer is number of zeros o f polynomial is 3

Explanation:

According to the fundamental theorem of algebra,the number of zeros is same as the degree of polynomial.

If the degree is n then number of zeros is n.

To find the degree of f(x)

f(x) = (x-15)(x+1)(x-10)

f(x) = x³ - 24x² + 125x + 15

From this we get degree of this polynomial is 3.

Therefore the number of zeros is 3

User Ashcatch
by
8.0k points
2 votes

Answer: 3 zeros.

Explanation:

According the Fundamental theorem of algebra, a polynomial of degree
n has
n roots.

When you apply the distributive property in the function given in the problem, you obtain the following polynomial:


f(x)=(x-15)(x+1)(x-10)=x^(3)-24x^(2)+125x+150

The highest exponent is 3, therefore the its degree is 3.

If the degree is 3 it has 3 zeros.

User Tanmay Patel
by
8.8k points

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