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HELP ASAP



GEOMETRY
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HELP ASAP GEOMETRY . . . . . .-example-1
User Pfulop
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1 Answer

6 votes

Answer:

1. y = -(2/5)x - (1/5)

2. y = -(9/5)x - 4

Explanation:

For 1:

Step 1: rewrite the equation of the given line in to slop-intercept form by solving for y

2x + 5y = 15

5y = -2x + 15 (subtract 2x from both sides)

y = -(2/5)x + 3 (divide both side by 5)

Step 2: Our line is parallel to this line, so it has the same slope, but a different y-intercept, so set up the equation...

y = -(2/5)x + b

We are given a point (x, y) of (2, -1), so plug that in and solve for b.

-1 = -(2/5)(2) + b

-1 = -4/5 + b (simplify)

4/5 -1 = b (add 4/5 to both sides to isolate b)

4/5 - 5/5 = b

-1/5 = b

So the equation of our line is y = -(2/5)x - (1/5)

For 2:

Step 1: Perpendicular lines have slopes that are opposite reciprocals of each other. That means you take the slope, flip the fraction, and change the sign.

Here our given line is y = (5/9)x - 4 so the slope 5/9

The opposite reciprocal of 5/9 is -9/5

We set up the equation

y = -(9/5)x + b

we are given a point (x, y) of (-5, 5), so plug that in and solve for b

5 = -(9/5)(-5) + b

5 = 9 + b

-4 = b

So our equations is y = -(9/5)x - 4

User Rohit Banga
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5.0k points