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Find the value of y round to the nearest tenth! laws of sin trigonometry!!!! help!!! please!!!!​

Find the value of y round to the nearest tenth! laws of sin trigonometry!!!! help-example-1
User Bier Hier
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1 Answer

7 votes

Answer:

43.5

Explanation:

We first need to find 'x', then the missing angle to solve for y.

We start with..

(Sin 42)/31 = (Sin X)/37

solving for X....

37(Sin 42)/31 = Sin X (multiply both sides by 37 to isolate Sin X)

0.798639756 = Sin X

Sin^(-1) 0.798639756 = X

53° = X

Now we can find the missing angle needed to solve for y....

42° + 53° + Y = 180°

So Y = 85°

Solving for y gives us...

(Sin 42)/31 = (Sin 85)/y

y(Sin 42) = 31(Sin 85) (cross multiply)

y = 31(Sin 85)/(Sin 42) (divide both sides by Sin 42 to isolate y)

y = 46.2 (rounded to the nearest tenth

User Joshmoto
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