Question

Find the x-intercept and y-intercept of the line. -3x+6y=11

Answer 1

x- intercept is at
`( - 3 (2)/(3) ,0)`.

y- intercept is at
`(0,1 (5)/(6) )`.

Explanation:

The x-intercept occurs when y=0.

Thus, substitute y= 0 into the equation to find the x- intercept.

-3x +6y= 11

When y= 0,

-3x +6(0)= 11

-3x= 11

x= 11 ÷ (-3)

`x = - (11)/(3) \\ x = - 3 (2)/(3)`

The y-intercept occurs at x= 0.

When x= 0,

-3(0) +6y= 11

6y= 11

y= 11÷ 6

`y = 1(5)/(6)`