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5 votes
Divide x^4 + 7 by x-3

User Beebek
by
7.4k points

2 Answers

2 votes

your answer would be:

x^3+3x^2+9x+27 with a remainder of 88

User Arshbot
by
7.2k points
4 votes

Answer:asdfsdf

Quotient : x^3 + 3x^2 +9x +27

Remainder : 88

Explanation:

Divide x^4 + 7 by x-3


(x^4+7)/(x-3)

to divide this we use long division

WE use 0 for other terms that are not given

x^4 + 0x^3 + 0x^3 + 0x +7

x^3 + 3x^2 +9x +27

--------------------------------

x-3 x^4 + 0x^3 + 0x^3 + 0x +7

x^4 -3x^3

-------------------------------------------(subtract it)

3x^3 +0x^2

3x^3 - 9x^2

-------------------------------------(subtract)

9x^2 + 0x

9x^2 - 27x

-----------------------------------(subtract)

27x + 7

27x -81

-----------------------------(subtract)

88

Quotient : x^3 + 3x^2 +9x +27

Remainder : 88

User Igor Dolzhenkov
by
6.6k points
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