193k views
4 votes
Find the center of the circle that can be circumscribed about EFG with E(4,4) F(4,2) G(8,2)

User Yanunon
by
8.1k points

1 Answer

3 votes

Answer:

The center of the circle is (6 , 3)

Explanation:

∵ The vertices of Δ EFG are E (4 , 4) , F (4 , 2) , G (8 , 2)

∵ The x-coordinates of E and E are equal ∴ EF is vertical

∵ The y-coordinates of F and G are equal ∴ FG is horizontal

∴ m∠EFG = 90°

∵ The circle is circumscribed about Δ EFG

∴ E , F , G lie on the circle

∵ m∠F = 90°

∴ EG is the diameter of the circle

∴ The center of the circle is the mid-point of EG

∵ The mid-point of EG is
((4+8)/(2),(4+2)/(2))=(6,3)

∴ The center of the circle is (6 , 3)

User Tinsa
by
7.5k points

Related questions

1 answer
4 votes
186k views
1 answer
3 votes
223k views
1 answer
1 vote
53.7k views