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What is the value of x, when x2 + 5 = 21?

User SoLoGHoST
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Hey there!


  • \bold{x^2+5=21}
  • Firstly, subtract by the number
    \bold{5} on each of your sides

  • \bold{x^2+5-5=21-5}

  • \bold{Cancel:5-5} because it gives us the result of
    \bold{1}

  • \bold{Keep:21-5} because it equals:
    \bold{16}

  • \bold{x^2=16}
  • Nextly, we have to take our square root

  • \bold{x=}±
    \bold{√(16)}
  • Solve the square root and you have found your answer

  • \boxed{\boxed{\bold{Answer:x=4[or]x=-4}}}
    \bold{\checkmark}

Good luck on your assignment and enjoy your day!

~
\bold{LoveYourselfFirst:)}

User TylerTemp
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