Question

What are zeros of f(x) = (x-3)(x+8)?

Answer 1

The zeros are -8,3

Explanation:

We can use the zero product property which says set each of the factors equal to zero

0 = (x-3)(x+8)

x-3 = 0 x+8 = 0

x-3+3=0=3 x+8-8 = 0-8

x= 3 x = -8