Question

The equation of the graphed line in slope point form using the point (2,-1 ) is blank and it’s equation in slope intercept is blank

Answer 1

`y=(1)/(4)x-(3)/(2)` (Slope intercept form)

`y+1=(1)/(4)(x_-2)` (Slope point form)

Explanation:

The slope of the line can be calculated as following:

`m=(-1-(-2))/(2-(-2))=1/4`

The the equation of the line in slope point form is:

`y-y_1=m(x_-x_1)`

Where (
`x_1`,
`y_1`) is a point of the line.

Then you must susbtitute the point given and the slope and you obtain:

`y+1=(1)/(4)(x_-2)`

The intercept form is:

`y=mx+b`

Where b is the y-intercept.

Solve for y from the equation of the line in slope point form obtained above, then:

`y+1=(x)/(4)-(2)/(4)\\y=(1)/(4)x-(2)/(4)-1\\y=(1)/(4)x-(3)/(2)`