Question

2. A lever has efficiency 60% and mechanical advantage 4, then

(i) Calculate effort required to lift 1000 N load. [250 N] (ii
(ii) Calculate velocity ratio of the lever. [VR = 6.66]
(iii) Find out output work to turn load up to 20 m. [20,000 Nm]
1:0​

Answer 1

(i) Effort = 250 N

(ii) Velocity ratio = 6.667

(iii) work output = 20 000 Nm

Step-by-step explanation:

Given: efficiency = 60%, mechanical advantage = 4.

(i) Mechanical advantage =
`(Load)/(effort)`

Load = 1000 N

⇒ Effort =
`(Load)/(Mechanical advantage)`

=
`(1000)/(4)`

= 250 N

Effort = 250 N

(ii) Efficiency =
`(Mechanical advantage)/(velocity ratio)` x 100%

Velocity ratio =
`(Mechanical advantage)/(Efficiency)` x 100%

=
`(4)/(60)` x 100

= 6.667

Velocity ratio = 6.667

(iii) Work output = Load x distance moved by load

= 1000 x 20

= 20 000

Work output = 20 000 Nm